1996 United States presidential election in Rhode Island
1996 United States presidential election in Rhode Island Turnout 64.8%[ 1] 11.8 pp
County Results Municipality Results
Clinton
40–50%
50–60%
60–70%
70–80%
Dole
40–50%
The 1996 United States presidential election in Rhode Island took place on November 5, 1996, as part of the 1996 United States presidential election . Voters chose four representatives, or electors to the Electoral College , who voted for president and vice president .
Rhode Island was won by President Bill Clinton (D ) over Senator Bob Dole (R -KS ), with Clinton winning 59.71% to 26.82% by a margin of 32.89%. Billionaire businessman Ross Perot (Reform Party of the United States of America -TX ) finished in third, with 11.20% of the popular vote.[ 2]
As of 2020, this was the most recent presidential election in which the town of Scituate voted for a Democrat.
Results
By county
County
Bill Clinton Democratic
Bob Dole Republican
Various candidates Other parties
Margin
Total votes cast
#
%
#
%
#
%
#
%
Bristol
12,257
56.56%
6,988
32.25%
2,426
11.19%
5,269
24.31%
21,671
Kent
41,048
57.35%
19,992
27.95%
10,516
14.70%
21,056
29.40%
71,526
Newport
18,951
54.00%
11,500
32.77%
4,645
13.23%
7,451
21.23%
35,096
Providence
134,866
63.58%
49,901
23.52%
27,355
12.90%
84,965
40.06%
212,122
Washington
25,958
52.09%
16,302
32.71%
7,572
15.20%
9,656
19.38%
49,462
Totals
233,050
59.71%
104,683
26.82%
52,551
13.47%
128,367
32.89%
390,284
See also
References