Oxford Township, Delaware County, Ohio

Oxford Township, Delaware County, Ohio
Oxford Township, Delaware County, Ohio
Township
	Fields in the township's far southwest
	Location of Oxford Township in Delaware County
	Coordinates: 40°24′10″N 82°58′51″W / 40.40278°N 82.98083°W
Country	United States
State	Ohio
County	Delaware
Area
• Total	19.41 sq mi (50.28 km2)
• Land	19.41 sq mi (50.27 km2)
• Water	0.004 sq mi (0.01 km2)
Elevation	968 ft (295 m)
Population (2020)
• Total	950
• Density	49/sq mi (19/km2)
Time zone	UTC-5 (Eastern (EST))
• Summer (DST)	UTC-4 (EDT)
FIPS code	39-59262
GNIS feature ID	1086053

Oxford Township is one of the eighteen townships of Delaware County, Ohio, United States. As of the 2020 census the population was 950.

Geography

Located in the northern part of the county, it borders the following townships:

Westfield Township, Morrow County - north
Peru Township, Morrow County - east
Kingston Township - southeast corner
Brown Township - south
Troy Township - southwest
Marlboro Township - northwest

The village of Ashley occupies part of northeastern Oxford Township.

Name and history

Oxford Township was founded in 1815.^[4]

It is one of six Oxford Townships statewide.^[5]

Government

The township is governed by a three-member board of trustees, who are elected in November of odd-numbered years to a four-year term beginning on the following January 1. Two are elected in the year after the presidential election and one is elected in the year before it. There is also an elected township fiscal officer,^[6] who serves a four-year term beginning on April 1 of the year after the election, which is held in November of the year before the presidential election. Vacancies in the fiscal officership or on the board of trustees are filled by the remaining trustees.